By Admin 
Mumbai Indians started IPL 2026 with a historic win. Chasing a big target of 221 runs in the second match of the edition played on Sunday, Rohit Sharma (78) and Ryan Rickelton (81) played explosive innings and made a partnership of 148 runs for the first wicket. Before this, Shardul Thakur took 3 important wickets including that of Ajinkya Rahane, for which he was adjudged Player of the Match. With this victory, the stain on MI was removed which was there for the last 13 years.
Biggest successful run chase of IPL
Mumbai Indians achieved the target of 221 runs with 5 balls remaining and won by 6 wickets. This is Mumbai Indians’ biggest successful run chase in IPL so far. Mumbai openers Ryan Rickelton and Rohit Sharma started cautiously, then started attacking from the third over. Rickelton scored 81 runs in 43 balls with the help of 8 sixes and 4 fours.
Rohit Sharma scored 78 runs at a strike rate of more than 200. In this stormy innings played in 38 balls, he hit 6 sixes and the same number of fours. During this period, Rohit also scored his fastest fifty in IPL history, he had completed 50 runs in 23 balls.
erase the curse of 13 years
Mumbai Indians had been losing the first match of IPL for the last 13 years, the team last won the first match in 2012. Now this is the first time after 13 years that MI has won its first match of the IPL edition. Mumbai’s next match is with Delhi Capitals in Delhi.
Shardul Thakur received POTM Award
Shardul Thakur made his debut on Sunday for Mumbai Indians, his 7th team in the IPL. In the very first match, he won the Player of the Match award for Mumbai. He performed brilliantly in bowling and while Jasprit Bumrah-Trent Boult could not take wickets, he took 3 wickets. Thakur first dismissed a dangerous batsman like Finn Allen (37), then sent Cameron Green (18) to the pavilion cheaply. After this he made captain Ajinkya Rahane walk. Ajinkya Rahane (67) and Angkrish Raghuvanshi (51) played half-centuries for KKR.