By Admin 
India has defeated Australia by 5 wickets in the third T20 match. The Australian team had scored 186 runs while playing first, in reply Team India won with 9 balls remaining. India has become the first country to defeat Australia in a T20 match at Bellerive Ground in Hobart. Washington Sundar played the match winning inning of 49 unbeaten runs.
Thanks to the half-centuries of Tim Davis and Marcus Stoinis, Australia had scored 186 runs in the first play. David contributed 74 runs and Stoinis contributed 64 runs. In bowling, the most successful bowler for India was Arshdeep Singh, who took 3 wickets.
Amazing batting of Washington Sundar
Abhishek Sharma again batted stormily, but was out after scoring 25 runs. On the other hand, Shubman Gill’s poor form continues, he was out after scoring only 15 runs. Captain Suryakumar Yadav was set, he scored 24 runs in 11 balls but could not convert it into a big innings. Tilak Verma was again given the responsibility of number-4, who scored 29 runs. Akshar Patel also got the start, but walked out after scoring 17 runs.
India had lost 4 wickets at the score of 111, when Washington Sundar came to bat. Batting with explosive style, he scored 49 runs in 23 balls. At the other end, Jitesh Sharma scored unbeaten 22 runs. Both of them made an unbeaten partnership of 43 runs to ensure the victory of Team India. Now 3 matches have been completed in the five-match series, after which India and Australia are tied at one each.
Australia’s first defeat in Hobart
Australia had earlier played 5 T20 matches at Bellerive Stadium in Hobart and had won all the matches. Here it has defeated West Indies twice, England twice and Pakistan once. But India has become the first country to defeat the Australian team here.